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1940 U.S. National Championships – Women's singles

First-seeded Alice Marble defeated second-seeded Helen Jacobs 6–2, 6–3 in the final to win the women's singles tennis title at the 1940 U.S. National Championships. The tournament was played on outdoor grass courts and held from September 2, through September 7, 1940 at the West Side Tennis Club in Forest Hills, Queens, New York.[1]

Women's singles
1940 U.S. National Championships
Final
ChampionUnited States Alice Marble[1]
Runner-upUnited States Helen Jacobs
Score6–2, 6–3
Details
Draw55
Seeds7
Events
Singles men women
Doubles men women
← 1939 · U.S. National Championships · 1941 →

The draw consisted of 55 players of which seven were seeded.

Seeds

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The eight seeded U.S. players are listed below. Alice Marble is the champion; others show in brackets the round in which they were eliminated.

  1. United States  Alice Marble (champion)
  2. United States  Helen Jacobs (finalist)
  3. United States  Pauline Betz (quarterfinals)
  4. United States  Dorothy Bundy (quarterfinals)
  5. United States  Sarah Cooke (third round)
  6. United States  Helen Bernhard (quarterfinals)
  7. United States  Virginia Wolfenden (quarterfinals)

Draw

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Final eight

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Quarterfinals Semifinals Finals
               
2 United States  Helen Jacobs 3 6 6
7 United States  Virginia Wolfenden 6 4 1
2 United States  Helen Jacobs 2 6 6
United Kingdom  Mary Hardwick 6 1 4
3 United States  Pauline Betz 7 1 2
United Kingdom  Mary Hardwick 5 6 6
2 United States  Helen Jacobs 2 3
1 United States  Alice Marble 6 6
1 United States  Alice Marble 6 6
6 United States  Helen Bernhard 2 3
1 United States  Alice Marble 6 6
United Kingdom  Valerie Scott 3 3
4 United States  Dorothy Bundy 6 4 3
United Kingdom  Valerie Scott 2 6 6

References

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  1. ^ a b Collins, Bud (2016). The Bud Collins History of Tennis (3rd ed.). New York: New Chapter Press. p. 499. ISBN 978-1-937559-38-0.